hash: fix total entries count
authorDharmik Thakkar <dharmik.thakkar@arm.com>
Thu, 9 May 2019 17:19:06 +0000 (17:19 +0000)
committerThomas Monjalon <thomas@monjalon.net>
Thu, 9 May 2019 20:31:29 +0000 (22:31 +0200)
In rte_hash, with current implementation, it is possible that keys
are stored at indexes greater than the number of total entries.

Currently, in rte_hash_free_key_with_position(), due to incorrect
computation of total_entries, application cannot free keys with
indexes greater than the number of total entries.

This patch fixes this incorrect computation of total_entries.

Bugzilla ID: 261
Fixes: 9d033dac7d7c ("hash: support no free on delete")
Cc: stable@dpdk.org
Reported-by: Linfan <zhongdahulinfan@163.com>
Suggested-by: Linfan <zhongdahulinfan@163.com>
Signed-off-by: Dharmik Thakkar <dharmik.thakkar@arm.com>
Acked-by: Yipeng Wang <yipeng1.wang@intel.com>
lib/librte_hash/rte_cuckoo_hash.c

index 1f5808e..2dc423f 100644 (file)
@@ -1594,7 +1594,9 @@ rte_hash_free_key_with_position(const struct rte_hash *h,
 
        unsigned int lcore_id, n_slots;
        struct lcore_cache *cached_free_slots;
-       const uint32_t total_entries = h->num_buckets * RTE_HASH_BUCKET_ENTRIES;
+       const uint32_t total_entries = h->use_local_cache ?
+               h->entries + (RTE_MAX_LCORE - 1) * (LCORE_CACHE_SIZE - 1) + 1
+                                                       : h->entries + 1;
 
        /* Out of bounds */
        if (key_idx >= total_entries)